Given the numbers x = a and y = –b, which statement is true? a. |x| = –a and –|y| = –b b. –|x| = a and –|y| = b c. |–x| = –a and |–y| = b d. |x| = a and |y| = b

choice D is correct, any number inside the absolute value sign is positive so choice A and C is eliminated, if there is a negative sign in front of the absolute value symbol, the number becomes negative which eliminates choice B. The only choice left is choice D

D. |x| = a and |y| = b , because modulus sign (| |) turns a negative number into positive

sss (side, side, side)

sas (side, angle, side)

asa (angle, side, angle)

aas (angle, angle, side)

hl (hypotenuse, leg)

the figures below are made out of circles, semicircles, quarter … find the area and the perimeter of each figure and give your answers as a completely simplified exact value in terms of π (no approximations). remember that we'll also have to cut whatever areas we get in half, since we're only dealing

step-by-step explanation: