The base of an isosceles triangle is 21 cm long. the altitude to the base is 9 cm long. what is the approximate measure of a base angle of the triangle?

Step-by-step explanation:

tan α=9÷(21/2)=18/21=6/7

α=arc tan(6/7)≈40.6°

solution:

→c= a b , that is product of a and b is possible only when when a is m × n matrix and b is n × p matrix.

that is, number of columns of a= number of rows of b.

so, size of matrix , c= a b is , if a = (m × n)matrix

b= (n × p)matrix

then a b = [ (m × n)matrix] ×[   (n × p)matrix ]

→→c= a b= [m × p ] matrix

→→size of product a b will be equal to = number of rows of a × number of columns of b

step-by-step explanation: