Which of the functions have a range of all real numbers? check all that apply. a. y = sec x b. y = tan x c. y = cot x d. y = csc x

B.y = tan x  and  C.y = cot x

Step-by-step explanation:

Range:

range is defined as the set of values that any given function y=f(x), can take for which the x values are defined. It is the value that y can take for the values of x.

Given:

From the given options

the range of tanx and cotx are all real numbers

as the period of tanx and cotx are π

where as range of secx is all real numbers except π/2 + n*π i.e.

(-∞ , -1] U [1 , + ∞)

And range of cscx is all real numbers except n*π i.e.

(-∞ , -1] U [1 , + ∞)

So from the given option:

option B and C are correct while A and D are not !

The answer is:  The correct options are B. Tan(x) and C. Cot(x)

The range is the output of a function when we evaluate the function with inputs (domain), not all functions have a range of all real numbers, however it's more common to find functions without range or domain restrictions.

Both options B. Tan(x) and C. Cot(x) have a range of all real numbers while the functions Sec(x) and Csc (x) have a restricted range.

Sec(x) and Csc(x):

Domain, all real numbers.

Range, from -1 to 1 or  [-1,1]

Tan(x) and Cot(x):

Domain, all real numbers except

Range, all real numbers.

Hence, the correct options are B. Tan(x) and C. Cot(x)

Have a nice day!

i dont know nkw

step-by-step explanation:

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logv3(x+2)=1

rewrite in exponential form:

logb(x) = y is equal to b^y =x

b = 3, y = 1

now solve for x:

3^1 = x+2)

x = 3-2

x = 1

see the picture for the graph.