If alpha and beta are the zeroes of the polynomial f(x)=x2- p(x+1) - c show that (alpha+1) (beta +1) = 1-c

see explanation

Step-by-step explanation:

Given

f(x) = x² - p(x + 1) - c

     = x² - px - p - c ← in standard form

with a = 1, b = - p and c = - p - c

Given that α and β are the zeros of f(x), then

α + β = - and αβ = , thus

α + β = - = p , and

αβ = = - p - c

-----------------------------------------------------------

(α + 1)(β + 1) ← expand factors

= αβ +α + β + 1 ← substitute values from above

= - p - c + p + 1

= - c + 1 = 1 - c ← as required

days of the week

step-by-step explanation:

javier earned more money then kyle, so that won't always be a constant term, but the days of the week do not change so that term is always constant.

edit: i meant

hello from mrbilldoesmath!

answer:   x (x+6)^2, choice b

discussion:

factor x out of the equation:

x^3 + 12x^2 + 36x = x (x^2 + 12x + 36).

note that 6+6 = 12 and 6*6 = 36 so the above factors into:

x (x+6)^2

which is choice b

you,

mrb