The work of a student to solve a set of equations is shown: equation a: y = 4 ? 2z equation b: 4y = 2 ? 4z step 1: ? 4(y) = ? 4(4 ? 2z) [equation a is multiplied by ? 4.] 4y = 2 ? 4z [equation b] step 2: ? 4y = 4 ? 2z [equation a in step 1 is simplified.] 4y = 2 ? 4z [equation b] step 3: 0 = 6 ? 6z [equations in step 2 are added.] step 4: 6z = 6 step 5: z = 1 in which step did the student first make an error? step 1 step 3 step 4 step 2

it is x equals 3   plese mark me really need it

step-by-step explanation:

hello from mrbilldoesmath!

answer:   (7x + 6y) ( 49x^2 - 42xy + 36y^2)

discussion:

in general, the factorization of a^3 + b^3 is

a^3 + b^ 3 = (a + b) ( a^2 - ab + b^2)

in our case note that 343 = 7^3 and 216 = 6^3 so the equation becomes:

343x^3 + 216y^3 = (7x)^3 + (6y)^3

if you think of a (above) as 7x and b as 6y the factorization becomes

343x^3 + 216y^3 =

((7x + 6y) (   (7x)^2 - 7x*6y + (6y)^2)   =

(7x + 6y) ( 49x^2 - 42xy + 36y^2)

you,

mrb

(a + b) (a^2 - a b + b^2)

what am i looking for finish the question.

step-by-step explanation: