Find the missing factor. 5y2 + 4y - 1 = (5y - 1)( )

(y + 1)

Step-by-step explanation:

Given

5y² + 4y - 1

To factorise the quadratic

Consider the factors of the product of the coefficient of the y² term and the constant term which sum to give the coefficient of the y- term

product = 5 × - 1 = - 5 and sum = + 4

The factors are + 5 and - 1

Use the factors to split the y- term

5y² + 5y - y - 1 ( factor the first/second and third/fourth terms )

= 5y(y + 1) - 1(y + 1) ← factor out (y + 1) from each term

= (y + 1)(5y - 1)

step by step resolutions

1) n+n+1+n+2=51

3n+3=51

3n=48

n=16

the three numbers are 16, 17 and 18.

2) x+15=4x

3x=15

x=5

radha is now 5 years old

3) the two digits are x and y.

y=3x

(10x+y)+(10y+x)=88

y=3x

11x+11y=88

y=3x

x+y=8

x+3x=8

x=2

the original number can be either 28 or 82.

4) n+(n+2)+(n+4)=48

3n+6=48

3n=42

n=14

the numbers are 14, 16 and 18.

5) y=x+3

10y+x+10x+y=143

y=x+3

11x+11y=143

y=x+3

x+y=13

x+x+3=13

2x=10

x=5

the original number can be 57 or 75.

hope this !