If the area of square 1 is 25 units square, and the area of square 2 is 16 units square, what is the perimeter of square 3

12 units²

Step-by-step explanation:

4^2+b^2=5^2

b=25-16

b^2=9

b=√9

b=3

there are 4 sides in a square so 3•4=12

< coa = 150 ( given)

as ba and bc are tangents

so oc and oa is perpendicular to cb and ab respectively because in circle normal passes through centre

so in quadrilateral oabc

< coa + < oab + < ocb + < abc = 360

150 +90+90 + < abc = 360

330 + < abc = 360

< abc = 360 -330 = 30

so < abc = 30

⭐dhruv⭐

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step-by-step explanation: