Let f(x)=x^2-6x+13. what is the vertex form of f(x)? what is the minimum value of f(x)?

The vertex form of a quadratic equation is:

the minimum value of f(x) is

Step-by-step explanation:

Given a quadratic equation of the form then the x coordinate of the vertex is

So for  

Therefore

The x coordinate of the vertex is:

The y coordinate of the vertex is:

By definition the minimum value of the quadratic function is the same as the coordinate of y of its vertex

So the minimum value  is

The vertex form of a quadratic equation is:

Where

a is the main coefficient.

h is the x coordinate of the vertex.

k is the y coordinate of the vertex.

So the vertex form of a quadratic equation is:

a.  

b. The minimum value is 4

Step-by-step explanation:

The given function is:

We add and subtract half the square of the coefficient of x.

This becomes:

The first three terms form a perfect square trinomial.

The function is now in the form:  , where V(h,k) is the vertex.

Therefore the vertex is (3,4).

The minimum value  is the y-value of the vertex, which is 4.

there are 70 more legs than eyes at the dog show (196 – 126 = 70). dogs have two more legs than eyes, and humans have the same number of legs as eyes. thus 70 is twice the number of dogs at the show, so the number of dogs is half of 70, which is 35. to get the number of humans, subtract 35 from 63: 63 – 35 = 28.

step-by-step explanation:

answer: i believe the answer is e

step-by-step explanation: