In a child's bank are 11 coins that have a value of s1.85. the coins are either
quarters or dimes. how many coins each does child have?
a. define your variables:
b. write the equations:
d. check:
c. solve:

The child has 6 dimes and 5 quarters.

Step-by-step explanation:

Let q and d represent the number of quarters and of dimes respectively.

Then q + d = 11 (Equation A), and ($0.25/quarter)q + ($0.10/dime)d = $1.85 (Equation B).

Multiply the 2nd equation by 100 to remove the decimal fractions:

25q + 10d = 185 (Equation C)

Now multiply the 1st equation by -10 to obtain -10q - 10d = -110 (Equation D), and combine this result with Equation C:

-10q - 10d = -110

25q + 10d = 185

15q         = 75, and so q = 75/15 = 5.

According to Equation A, q + d = 11.  Replacing q with 5, we get:

5 + d = 11, and so d = 6.

The child has 6 dimes and 5 quarters.

the radius is 2 times the diameter.

step-by-step explanation: