Apolynomial has been factored, as shown below:
f(x) = (x - 3)(x + 8)(x - 11)
what are the zeros of the polynomial?
3, 8, 11
3,-8, 11
-3, 8, -11
-3,3, -8,8, -11, 11

  3, -8, 11

Step-by-step explanation:

The first factor is zero when x=3.

The second factor is zero when x=-8.

The third factor is zero when x=11.

Whenever any factor is zero, the polynomial is zero.

The zeros are 3, -8, 11.

option (b) is correct

step-by-step explanation:

to find the solution of this system, we need to convert it into reduced row-echelon form. we have,

after applying row operations r2 -> r2/2 and r3 -> r3/3, we get,