Solve the inequality n/-3+ 8 > 6.
a.) n > -6
b.)n > 42
c.)n < 6
d.)n > -42

C.) n < 6

Step-by-step explanation:

Subtract 8:

n/-3 > -2

Multiply by -3. The negative multiplier requires the comparison be reversed:

n < 6

x = ± 6i

step-by-step explanation:

x^2 = -36

take the square root of each side

sqrt(x^2) = sqrt(-36)

we know sqrt(ab) = sqrt(a) sqrt(b)

x = ±sqrt(36) sqrt(-1)

we know that sqrt (-1) = i

x = ± 6i

it is contrapositive

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