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lloyd's bakery sold one customer 9 dozen chocolate cookies and 8 dozen oatmeal cookies for $110. the bakery also sold another customer 9 dozen chocolate cookies and 5 dozen oatmeal cookies for $89. how much do the cookies cost?

a dozen chocolate cookies cost $ and a dozen oatmeal cookies cost $

A dozen chocolate cookies cost $6

and a dozen oatmeal cookies cost $7

Step-by-step explanation:

Let's assume that cost of 1 dozen chocolate cookies = x

Let's assume that cost of 1 dozen oatmeal cookies = y

then we get equations:

9x+8y=110...(i),

and 9x+5y=89...(ii)

Solve equation (i) for x

9x+8y=110

9x=110-8y

...(iii)

plug (iii) into (ii)

9x+5y=89

plug y=7 into (iii)

So the final answer is given by:

A dozen chocolate cookies cost $6

and a dozen oatmeal cookies cost $7

circle area = pi * radius^2

if diameter = 10 then radius = 5

circle area = pi * 5^2

circle area = pi * 25

circle area = 78.5398163397 square units

step-by-step explanation: