The population of a heard of cattle numbered was 5000 to begin with and was 10,000 after 10 years. if the population was growing exponentially, what was the growth rate? show all work
a) r=2
b) r=20
c)r=0.69
d)r=6.9

. The closest value from your given choices is C)r=0.69

Step-by-step explanation:

To solve this we are using the standard exponential growth equation:

where

is the final population after years

is the initial population

is the growth rate in decimal form

is the time in years

We know from our problem that the initial population is 5000, the final population is 10000, and the time is 10 years, so , , and .

Let's replace the values and solve for :

Divide both sides by 5000

Take root of 10 to both sides

Subtract 1 from both sides

We can conclude that the growth rate of our exponential equation is . The closest value from your given choices is C)r=0.69

(2x + 16) + (x) = 180

step-by-step explanation:

given,

abcd is a quadrilateral inscribed in a circle

angle a is labeled x plus 16, (x + 16)

angle b is labeled x degrees, (x)

angle c is labeled 6x minus 4, (6x – 4)

angle d is labeled 2x plus 16, (2x + 16)

what equation can be used to solve for angle b?

we know that the sum of the opposite angles of a simple quadrilateral inscribed in a circle is 180 degrees.

angle b is opposite angle d

therefore, angle b + angle d = 180

(x) + (2x + 16) = 180 

same as (2x + 16) + (x) = 180

47.28 or 47.2857143

step-by-step explanation:

you just divide 331 by 7 and you get that answer. ( i think so tho)