11.
♡
what is the standard form of the equation of a circle with center (3,-2) and radius 4?
ao (x - 3)2 + (y + 2)2 = 16
bo (x – 3)2 + (y + 2)2 = 4
c. (x + 3)2 + (y – 2)2 = 16
d. (x – 3)2 + ( – 2)2 = 16

(x-3)^2+(y+2)^2=16

Step-by-step explanation:

The standard form of a circle is

where h and k are the coordinates of the center and r is the radius, which is squared.  From our information, h is 3--> (x-3) and k is -2--> (y-(-2))--> (y+2) and 4 squared is 16.  Your choice is A.

b. x- 48 =120

step-by-step explanation:

explanation:

previous steps have made pa≅ pb ≅ st ≅ su. setting the compass width to ab allows you to make tu the same length. then δstu ≅ δpab by the sss congruence postulate, and ∠p ≅ ∠s by the reason cpctc.