Find the perimeter of a field that has length 2/x + 1 and width 5/x^2 -1.

a) 2x + 3/(x + 1)(x - 1)
b) 10/(x + 1)(x - 1)
c) 7/(x + 1)(x - 1)
d)4x + 6/(x + 1)(x - 1)

D)4x + 6/(x + 1)(x - 1)

Step-by-step explanation:

A field is basically a rectangle, so to find the perimeter of our field we are using the formula for the perimeter of a rectangle

where

is the perimeter

is the length

is the width

We know from our problem that the field has length 2/x + 1 and width 5/x^2 -1, so and .

Replacing values:

Notice that the denominator of the second fraction is a difference of squares, so we can factor it using the formula where is the first term and is the second term. We can infer that and . So, . Replacing that:

We can see that the common denominator of our fractions is . Now we can simplify our fraction using the common denominator:

We can conclude that the perimeter of the field is D)4x + 6/(x + 1)(x - 1).

the data of the detroit pistons in numerical order from least to greatest is 0.30, 0.37, 0.55, 0.62, 0.69, 0.72, 0.73, 0.75, 0.77, 0.78, 0.80, 0.81, 0.81, 0.83, 0.84, 0.89

the data of the miami heat in numerical order from least to greatest is 0.50, 0.50, 0.56, 0.57, 0.67, 0.72, 0.72, 0.72, 0.75, 0.75, 0.76, 0.81, 0.82, 0.90, 1.00, 1.00

the detroit pistons median : 1.52

the miami heat median: 1.47

the iqr of this data is 0.05

answer4 to the second power is 16

and 4 to the third power is 64,