Carter wants to know if warming up will runners sprint faster. thirty track and field athletes volunteered to participate in his study. he randomly assigns 15 athletes to warm-up for 10 minutes. all 30 participants sprint the same distance. he calculates the mean for each group and determines that the mean for the warm-up group was 10.7 seconds, and the mean for the other group was 13.2 seconds. to test the difference of means he re-randomized the data 54 times, and the differences are plotted in the dot plot below. what can carter conclude from his study?
the graph shows: (3) -2.5, (6) -2.0, (9) -1.5, (12) -1.0, (6) -0.5, (4) 0.0, (3) 0.5, (7) 1.0, (3) 1.5, and (1) 2.0. the parenthesis is how many dots there is at each point.

the difference in the means is significant because a difference of 2.5 is very likely.
the difference in the means is not significant because a difference of 2.5 is very likely.
the difference in the means is significant because a difference of 2.5 is not very likely.
the difference in the means is not significant because a difference of 2.5 is not very likely.

The correct option which states the conclusion made from the carter study is .

Further explanation:

In the question it is given that thirty track and field athletes volunteered to participate in the study to determine the effect of warming up on the performance of athletes.  

To obtain the data for the study carter randomly assign athletes to the warm up of minutes and the remaining athletes didn’t do any warm up.  

After the warm up of athletes all the athletes were made to sprint for the same distance.  

After the sprint it was observed that the mean time for the warm-up group was seconds and the mean time for other group was seconds.  

The mean difference of the data obtained is calculated as follows:  

The mean differences are plotted in the dot plot in the figure attached below.  

The frequency of difference is which is not likely to happen in the graph as it shown in the dot plot.  

Option A  

The difference in the means is significant because a difference of is very likely.  

From the figure attached below it is observed that the difference in the means is not significant because the difference of is not very likely.  

So, as per the above statement it is concluded that option A is incorrect.  

Option B  

The difference in the means is not significant because a difference of is very likely  

From the figure attached below it is observed that the difference in the means is not significant because the difference of is not very likely.  

So, as per the above statement it is concluded that option B is incorrect.  

Option C  

The difference in the means is significant because a difference of is not very likely.  

From the figure attached below it is observed that the difference in the means is not significant because the difference of is not very likely.  

So, as per the above statement it is concluded that option C is incorrect.  

Option D  

The difference in the means is not significant because a difference of is not very likely.  

From the figure attached below it is observed that the difference in the means is not significant because the difference of is not very likely.  

So, as per the above statement it is concluded that option D is correct.  

Therefore, the correct option which states the conclusion made from the carter study is .

Learn more:

1.A problem on composite function link  

2.A problem on simplification link  

3.A problem in inverse function link  

Answer details  

Grade: High school  

Subject: Mathematics  

Chapter: Dot plot  

Keywords: Plot, dot plot, statistics, probability, mean, significant, most likely, mean difference, differences, athlete, warm up, very likely,

median, mode, frequency, frequency distribution,

jhfdergmllm: $"$& (& #@$& () 9887¥€¢£`~¥°℅™℅℅℅=

step-by-step explanation:

π^°×{{€€

i'm sure goog can you get that answer