In the rho. bus, m angle 1 =4y-2. find the value of y.

y = 23

Step-by-step explanation:

The diagonals of a rhombus are perpendicular bisectors of each other, thus

∠1 = 90° and ∠1 = 4y - 2, so equating gives

4y - 2 = 90 ( add 2 to both sides )

4y = 92 ( divide both sides by 4 )

y = 23

< coa = 150 ( given)

as ba and bc are tangents

so oc and oa is perpendicular to cb and ab respectively because in circle normal passes through centre

so in quadrilateral oabc

< coa + < oab + < ocb + < abc = 360

150 +90+90 + < abc = 360

330 + < abc = 360

< abc = 360 -330 = 30

so < abc = 30

⭐dhruv⭐

angle addition postulate

2x=56

step-by-step explanation: