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Mathematics, 29.12.2019 04:31 Woodlandgirl14

The work of a student to solve a set of equations is shown:

equation 1: m = 8 + 2n
equation 2: 6m = 4 + 4n

step 1: βˆ’6(m) = βˆ’6(8 + 2n) [equation 1 is multiplied by βˆ’6.]
6m = 4 + 4n [equation 2]
step 2: βˆ’6m = βˆ’48 βˆ’ 12n [equation 1 in step 1 is simplified.]
6m = 4 + 4n [equation 2]
step 3: βˆ’6m + 6m = βˆ’48 βˆ’ 12n + 4n [equations in step 2 are added.]
step 4: 0 = βˆ’48 βˆ’ 8n
step 5: n = βˆ’6

in which step did the student first make an error?
step 3
step 5
step 4
step 2

ansver
Answers: 1

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The work of a student to solve a set of equations is shown:

equation 1: m = 8 + 2n
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