Drag each tile to the correct box. arrange the equations in order from least to greatest bed on their solution. equation a: 5( x-6)+3x=3/4(2x-8) equation b: 2.7(5.1x+4.9)=3.2+28.9 equation c: 5(11x-18)=3(2x+7)

B

C

A

Step-by-step explanation:

Find the value of x in each equation then compare the solutions from the least to the greatest

In A

5( x-6)+3x=3/4(2x-8) Open brackets

5x-30+3x=3/2x-6

5x+3x-30=3/2x-6

8x-3/2x=-6+30collect like terms

16x-3x=48

13x=48dived both sides by 13

x=48/13 = 3.7

In B

2.7(5.1x+4.9)=3.2+28.9open bracket

13.77x+13.23=32.1

13.77x=32.1-13.23collect like terms

13.77x=18.87

x=18.87/13.77divide both sides by 13.77

x=1.37

In C

5(11x-18)=3(2x+7)open brackets

55x-90=6x+21

55x-6x=21+90collect like terms

49x=111divide both sides by 49 to get x

x=111/49 = 2.27

From the solutions, the least value of x is in B, then C ,and finally A

step-by-step explanation: so we look at the formula un = a + (n-1)d

un is the amount of seats

n is the nth term aka row number

a is the original sequence/row number

d is the difference between each term

so in this a=22 d=6 and n can remain as n because we are simply formjng a rule

lets put these in the equation

un=22+(n-1)(6)

this is your answer to part a

however

lets double check that this is correct, we'll try putting it into the second term

un=a+(n-1)d

u2=22+(2-1)(6)

u2=22+6

u2=28

as the question said the second row has 28 seats so now we know the formula we made is correct.

as for part b

un=a+(n-1)

its asking us to find a row with 100 seats.

remember un was the amount of seata so all we do is substitute this in.

un=100 a=22 d=6

un=a+(n-1)d

100=22+(n-1)(6)

so now we simplify to find n which is the row number.

100-22=22+(n-1)(6)-22

78=(n-1)(6)

78/6=(n-1)(6)/6

13=n-1

13+1=n-1+1

14=n

so now we know that in the 14th row there is 100 seats.

hope this and that you understood! its my first time using the app or anyone out on here : p its also me to revise so a bunch! ask more questions if you dont understand ☺