The length of a rectangle is two more than its width. find the perimeter of this rectangle if its area is 15 ft.²

Perimeter = 16ft

Step-by-step explanation:

Let the width(w) of the rectangle be x ft

The length(l) of the rectangle will be (x + 2) ft

Area of the rectangle is 15ft²

Area of a rectangle = l × w

(x + 2)x = 15

x² + 2x - 15 = 0

Applying the quadratic formula;

x = (-b ± ) ÷ 2a

x = (-2 ± ) ÷ 2

x = 3 or -5

Since the width can't be negative, we take 3ft to be the value of our width

The length is therefore 3ft + 2ft = 5ft

Perimeter(p) = 2l + 2w

p = 2(5) + 2(3) = 16ft

the answer is here: : )

:

problem:

f(x) = - 2/3x + 5; f(5/2)

substitute 5/2 in for x:

f(5/2) = -2/3(5/2) + 5

simplify the right side:

f(5/2) = -5/3 + 5

f(5/2) = 10/3

f(5/2) = 10/3

i hope this !