Afootball is kicked at ground level with an initial velocity of 64 feet per second

find the height after 3 second and use one of the three forms and say which one would be the best to use and why

y= -16t^2+64t
y= -16(t-2)^2 + 64
y= -16t(t-4)

The height of the football is 48 feet after 3 seconds

The first equation y = -16t² + 64t is the best

Step-by-step explanation:

* Lets explain how to solve the problem

- The equation of motion of an object on air without any

 external force is y = ut + 1/2 at², where y is the height of the

 object from the ground, u is the initial velocity, a is the

 acceleration of gravity and t is the time

* Lets solve the problem

- A football is kicked at ground level with an initial velocity of

 64 feet per second

∴ u = 64 feet per seconds

∵ The football is kicked upward

∴ a = -32 feet per seconds²

∵ y = ut + 1/2 at²

∴ y = 64t + 1/2 (-32)t²

∴ y = 64t - 16t²

* We will use the first equation y = -16t² + 64t

∵ y = -16t² + 64t

- We need to find the height of the football after 3 seconds

∵ t = 3 seconds

∴ y = -16(3)² + 64(3)

∴ y = 48

∵ y represents the height of the football

∴ The height of the football is 48 feet after 3 seconds

ab: 2 n83b8eb7ebi. 8e yen in

because they could drop even lower..