Two cars started moving from san jose to san diego. the speed of the faster car was 12 mph less than twice the speed of the other one. in 6 hours the faster car got to san diego, and by that time the slower one still was 168 miles away from the destination. find their speeds.

The speed of the faster car is 68 miles/hr and speed of slower car is 40 miles/hr.

Step-by-step explanation:

Let the speed of the slower car be x

Now we are given that The speed of the faster car was 12 mph less than twice the speed of the other one.

So, Speed of faster car = 2x-12

Now we are given that In 6 hours the faster car got to San Diego, and by that time the slower one still was 168 miles away from the destination.

So, faster car completes the journey in 6 hours

Distance =

So, Distance traveled by faster car =

Distance traveled by slower car in 6 hours =

Since we are given that when faster car completes the journey at that time slower car was 168 miles away from the destination .

A.T.Q

So, speed of slower car is 40 miles/hr.

Speed of faster car = 2x-12 =2(40)-12=80-12=68 miles/hr.

Hence the speed of the faster car is 68 miles/hr and speed of slower car is 40 miles/hr.

∠acb = 8°

step-by-step explanation:

∠xba lies on the circle and is half the measure of the intercepted arc ax

hence

measure of arc ax = 2 × 42° = 84°

∠acb is outside the circle and is

∠acb = (arcab - arcax ), hence

∠acb = 0.5 (100 - 84) = 0.5 × 16° = 8°