Arectangle has a perimeter of 76 cm. its length is 5 more that twice its width. the system of equation below can be use to fine the length, l, and the width, w, of the rectangle 2l+2w=76,l=2w+5

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Step-by-step explanation:

the perimeter of a rectangle is given by the following equation:

if a rectangle has a perimeter of 76cm and its length  is 5 plus the double of its width we can use a system of equations to find the length , and the width .

For the perimeter of the rectangle

where is its length, and   is its width, 76 is the perimeter of the rectangle in cm.

We know that the lengh of the rectangle is 5 plus the double of its width, writing the equation:

Substituting the equation above in

We got that the rectangle width is w=11cm

Substituting w in the equation

We got that the rectangle length is l=27cm

Verifying the values obtained

with l=27 and w=11

Satisfying the equation

answer: asdfghjkl,mnbv

step-by-step explanation:

i can't solve unless i know what the line is

step-by-step explanation:

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