Asubmarine is at a depth of 2 1/3 km below sea level and if it starts ascending at the rate of 800m/h. then find its position after 2 hours?

66 ⅔ m

Step-by-step explanation:

2 ⅓ km can be written in improper form as 5/3 km.

There's 1000 m in 1 km, so we can convert this:

5/3 km × (1000 m / km) = 5000/3 m

The submarine rises at 800 m/h.  So after 2 hours:

distance = rate × time

d = 800 m/h × 2 h

d = 1600 m

So the new position is:

5000/3 m − 1600 m

5000/3 m − 4800/3 m

200/3 m

66 ⅔ m

region b will make the inequalities y < 2x + 1 and y > -x - 2 true ⇒ answer a

step-by-step explanation:

* lets study the graph and the inequality to solve the question

- the inequality y > -x - 2

∵ the form of the inequality is y > mx + c , m is the slope of the line

  and c is the y-intercept (the line intersect y-axis at point (0 , c)

∴ c = -2 that means the line intersect the y-axis at point (0 , -2)

∵ the sign of the inequality is >

∴ we shad the part over the line

  region a and b

- the inequality y < 2x + 1

∵ the form of the inequality is y > mx + c , m is the slope of the line

  and c is the y-intercept (the line intersect y-axis at point (0 , c)

∴ c = 1 that means the line intersect the y-axis at point (0 , 1)

∵ the sign of the inequality is <

∴ we shad the part under the line

  region b and c

∵ the common region between the two lines is region b

∴ region b will make the inequalities y < 2x + 1 and y > -x - 2 true