If g(x)= square root x-2-3 what is the range of g(x)? a.(0,♾) b. (-1,♾) c. [-2,♾) d. [-3,♾)

D

Step-by-step explanation:

g(x) = √(x - 2) - 3

The range is all the possible values of g(x).  Since we can't take the square root of a negative number, the lowest that g(x) can be is:

g(x) = √0 - 3

g(x) = -3

The highest that g(x) can be is:

g(x) = √∞ - 3

g(x) = ∞

So the range is:

[-3, ∞)

henry ordered 5 large pizzas

step-by-step explanation:

sorry no step by step

answer: just subtact the units and then add the non negative : happy to

step-by-step explanation: