Samara is adjusting a satellite because she finds it is not focusing the incoming radio waves perfectly. the shape of her satellite can be modeled by y^2=2(x+6), where x and y are modeled in inches. she realizes that the static is a result of the feed antenna shifting slightly off the focus point. what is the focus point of the satellite?

(-5.5,0)

Step-by-step explanation:

The question is on finding the focus point of a parabola

Given y²= 2(x+6)(a)

Compare equation (a) with the standard equation  (y-b)²= 2p(x-a)

y²= 2(x+6)can be written as (y-0)²=2(x+6)

(y-0)²=2(x+6)

(y-b)²= 2p(x-a)

2p=2divide both sides by 2 to get p

p=2/2=1

For  the vertex (a,b)⇒(-6,0)

For  the focus point ( a+p/2, b)(b)

Substitute values i equation (b) above

(-6+1/2 ,0) =(-5.5, 0)

b i think

step-by-step explanation:

not really sure

b. 6

step-by-step explanation:

we are given the table representing an exponential function.

we can see from the table that, as x is increasing, the value of y is increasing in the power of 6.

i.e. the following relation is obtained,

x = 1, y = 6

x = 2, y = 36 =

x = 3, y = 216 =

x = 4, y = 1296 =

x = 5, y = 7776 =

so, the geometric series obtained is .

thus, the common ratio is given by = = 6.

hence, the common ratio is 6.