Given: lmnb is a square, lm = 20cm, p∈ lm , k ∈ pn , pk = 1 5 pn, lp = 4 cm find: area of lpkb

  80 cm²

Step-by-step explanation:

Trapezoid LPKB has area ...

  A = (1/2)(b1 +b2)h = (1/2)(4 +20)(20) = 240 . . . . cm²

Triangle BPN has area ...

  A = (1/2)bh = (1/2)(20)(20) = 200 . . . . cm²

Triangle BKN has a height that is 4/5 the height of triangle BPN, so will have 4/5 the area:

  ΔBKN = (4/5)(200 cm²) = 160 cm²

The area of quadrilateral LPKB is that of trapezoid LPNB less the area of triangle BKN, so is ...

  240 cm² - 160 cm² = 80 cm²

the answer is c just got it on ed

step-by-step explanation:

75

step-by-step explanation:

you do x-29=46 (the number of cantaloupes sold)

in order to find x, you have to find what minus 29 equals 46, meaning you'd have to add 29 to 46.

29+46=75

if you replace x with 75, the equation looks like:

75-29=46

x=75