Find the interval of the equation which function f is concave up or down locate inflection point f(x)=(x+2)^3

We need to compute and study the sign of the second derivative:

So, we have

So, this function is concave down before -2 (the second derivative is negative), it changes at x=-2 (inflection point), and it's concave up after -2 ( the second derivative is positive)

here you hope this .

step-by-step explanation:

hypotenuse = √(15² + 8²)

=  √(225 +64)

=  √(289) = 17

sin(x) = cos(y) = 8/17

they are identical so long as you are doing the sine of one angle and the cosine of the only other angle that isn't the right angle.

true

step-by-step explanation: