What is the equation of a line that passes through -6, two and has a slope of -1/2

  slope (y2-y1)/(x2-x1)

m = (q--q)(p--p)

m = 2q/2p

m=q/p

point slope form

y-y1=m(x-x1)

y-q =q/p(x-p)

distribute

y-q=q/p *x -q

add q to each side

y = q/p *x

Step-by-step explanation:

the required function is .

step-by-step explanation:

from the given table it is noticed that the graph passing through (-3,7), (0,4), (3,1) and (8,-4).

it is a linear function because the value of y is decrease by one as the value of x increase by 1.

the slope of the function is

the slope of the function is -1 and the y-intercept is 4.

the slope intercept form is

where, m is slope and b is y-intercept.

therefore the required function is . the graph of this function is shown below.

its 8

step-by-step explanation: