The circle below is centered at the point (-3,4) and has a radius of length 3.
what is its equation?
a. (x+ 3)^2 + (x-4)^2 = 9
b. (x-3)^2 + (x+4)^2=9.
c. (x+4)^2 + (x-3)2 =3^2
d. (x-4)^2 + (x+3)^2 =3^2

(x + 3)^2 + (y - 4)^2 = 3^2 = 9    This matches Answer A.

Step-by-step explanation:

Start with the standard equation of a circle with center at (h, k) and radius r:

(x - h)^2 + (y - k)^2 = r^2

Here the given point (h, k) is (-3, 4) and the radius is 3.

Substituting these values into the above equation, we get:

(x + 3)^2 + (y - 4)^2 = 3^2 = 9    This matches Answer A.

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