Calculate ∫c(3(x2−y)i⃗ +6(y2+x)j⃗ )⋅dr⃗ if: (a) c is the circle (x−3)2+(y−1)2=16 oriented counterclockwise. ∫c(3(x2−y)i⃗ +6(y2+x)j⃗ )⋅dr⃗ = 0 (b) c is the circle (x−a)2+(y−b)2=r2 in the xy-plane oriented counterclockwise. ∫c(3(x2−y)i⃗ +6(y2+x)j⃗ )⋅dr⃗ =

g(x) is the negative form of f(x)? because whenever its the negative form it reflects its self over the x axis. idk if this is right though.

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what are you trying to solve here

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where is abdul's work? don't see that anywhere posted : /

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if i'm not wrong, i would say that the third angle has (72) because the three sides of all triangles have 180 degrees and if we subtract 180 - 62 - 40 = (72) / but i'm not sure about 40 yd.