1. in a game, if you roll a 6 on a 6-sided number cube, you lose a turn. (a) what is the probability that you roll a 6? explain your reasoning. (b) what is the probability that you don’t roll a 6? explain your reasoning. (c) what is the probability that you either roll a 6 or do not roll a 6? explain your reasoning. (d) suppose you rolled the 6-sided number cube 120 times, how many times would you expect to roll a 6? explain and show all of your work.

Try this options:

a. total - 6 digits, '6' - 1 digit, then probability of rolling a '6' is 1/6;

b. total - 6 digits, '6' - 1 digit, then probability of rolling 1,2,3,4,5 is 5/6;

c. if probability of rolling a '6' is p and not rolling a '6' is q, then p+q=1;

d. if expected probability of one rolling a '6' is 1/6, then numbers of times of rolling a '6' during 120 times is 120/6=20 times.

if you mean

then it's c. 8, -7/3

but if you mean

then it is

1/3 + 1/3 ≠ 2/6 because 1/3 alone = 2/6  

step by step explanation:

1/3 + 1/3 = 2/3       2/3=4/6