What transformation has changed the parent function f(x) = 3(2)x to its new appearance shown in the graph below?

exponential graph passing through point 0, 1.

f(x) + 2
f(x) − 2
f(x + 2)
f(x − 2)

Second Option

f(x) − 2

Step-by-step explanation:

The function passes through point (0, 3) because:

Then, if the transformed function passes through the point (0, 1) then this means that the graph of was moved vertically 2 units down.

The transformation that displaces the graphically of a function k units downwards is:

Where k is a negative number. In this case

Then the transformation is:

and the transformed function is:

(0,-3) see attached graph

step-by-step explanation:

a. to solve the system, graph the two equations.

x = y+3 becomes y=x-3 has m=1/1 and b=-3. start at (0,-3) on the y-axis and plot a point. then move up 1 unit and 1 unit to the right. plot a point and connect.

y=-4x+3 has m =-4/1 and b=-3. start at (0,-3) on the y-axis and plot a point. then move down four units and to the right 1 unit. plot a point and connect.

the solution is the point (x,y) where the two lines intersect. by the graph below it is (0,-3).

b. to solve by substitution, substitute y = -4x-3 into x= y+3

x= (-4x-3) +3

x=-4x

5x=0

x=0

now substitute x = 0 back in to find y.

y= -4(0)-3

y=0-3

y=-3

solution is (0,-3)

c. use elimination by adding the equations together.

x-y=3

4x+y=-3

5x=0

x=0

then substitute into one equation to find y.

y=-4(0)-3

y=-3

answer: my brother can figure it out, imma go get him so i can answer : ) edit: my brother is sleeping, sorry man

step-by-step explanation: