Which is the equation of a parabola with focus (-2, -4) and vertex (-4, -4)?
a.(y+4)^2=8x+4
b.(y+4)=8x^2+4
c.(y+4)^2=8(x+4)
d.(y+4)^2=8(x+4)^2

C.

Step-by-step explanation:

If we plot the vertex and the focus, since the parabola wraps itself around the focus, we can see that this is parabola that opens up to the right.  The distance between the vertex and the focus is 2 units.  The equation for this type of parabola is:

where h and k are the coordinates of the vertex and p is the distance between the vertex and the focus.  We already know all of that info so we can jump right to filling in the equation:

which of course simplifies to your

the value of v.w= -12.

step-by-step explanation:

we are given three vector r,v and w as:

r = < 5, -5, -2> ; v = < 2, -8, -8> ; w = < -2, 6, -5>

we know that r,v and w could also be represented as:

r=5i-5j-2k

v=2i-8j-8k

and w= -2i+6j-5k

where i,j and k are the unit vectors of x,y and z-axis respectively.

also we know that it has the following property:

i.i=1 ; j.j=1; k.k=1

and i.=j.i=i.k=k.i=j.k=k.j=0

i.e. when we multiply two vectors or we find it's dot product we need to only multiply the components of x coordinates with each other; y with each other and z with each other.

hence, v.w= (2i-8j- -2i+6j-5k)

                  = 2×(-2)+(-8)×(6)+(-8)×(-5)

                  = -4-48+40

                  = -12

hence, v.w= -12

b

step-by-step explanation:

it have 5 sides and 5 identicle angle.the rest does not have the same property as b.

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