Find the points on the curve where the tangent is horizontal or vertical. if you have a graphing device, graph the curve to check your work. (enter your answers as a comma-separated list of ordered pairs.)x = t^3 - 3t, y = t^2 - 4

There is a horizontal tangent at (0,-4)

The tangent is vertical at (-2,-3) and (2,-3).

Step-by-step explanation:

The given function is defined parametrically by the equations:

and

The tangent function is given by:

The tangent is vertical at when

When t=1,

and

When t=-1,

and

The tangent is vertical at (-2,-3) and (2,-3).

The tangent is horizontal, when or  

When t=0,

and

There is a horizontal tangent at (0,-4)

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step-by-step explanation:

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it’s supposed to be -4+45=41

step-by-step explanation: