Giving brainliest
a rectangular area is to be enclosed with 12m of fencing.

a) what is the maximum area that can be enclosed if the fencing is used on all four sides. what are the dimensions of this optimal shape?

b) suppose an existing hedge is used to enclose one side. determine the maximum area that can be enclosed. what are the dimensions in this shape?

c) suppose two perpendicular hedges enclose the area on two sides. what are the dimensions of the maximum area that can be enclosed?

The dimensions of the region which enclose the maximal area will be:  Length = 162 feet and Width = 108 feet.

Explanation

According to the below diagram, the total rectangular area is divided into two separate regions by a vertical segment.

Suppose, the length and width of the rectangular area are  L and W respectively.

So, the length of that vertical segment will be equal to the width, W.

If the four walls of the rectangular area and the vertical segment are made up of fencing, then the total fence required  feet.

Given that, the farmer has 648 feet of fencing. So, the equation will be

Now, the area of the rectangular area:  

Substituting equation (1) into equation (2) , we will get

Taking derivative on the both sides of the above equation with respect to W, we will get

Now, A will be maximum when. So

Plugging this  into equation (1)

So, the dimensions of the region which enclose the maximal area will be:  Length = 162 feet and Width = 108 feet.

Step-by-step explanation:

(f - g)(x) = 5x^3 - 3

step-by-step explanation:

rearrange these functions vertically, with like terms in separate columns:

f(x) = 5x^3 - 2

g(x) =         +1

now subtract, column by column:

(f - g)(x) = 5x^3 - 3

it is c, trust i got your back lol

step-by-step explanation: