Abag contains only 2 green boxes, 2 red boxes, and 3 blue boxes. all of the boxes are the same size and texture. one box is taken from the bag at random and replaced. a second box is taken out at random. what is the probability that the first box os green and the second is blue?

Probability=number of favorable outcomes/ number of all possible outcomes

P(1st green and 2nd blue) = 2/6 x 3/6 = 1/6

what are ur choices?

step-by-step explanation: given equation a = h(b 1+b 2)

also we are given values of a, h and b 1 as :

a = 16, h = 4, and b 1 = 3.

in order to solve it for b 2, we need to plug the given values of   a, h and b 1 .

therefore, plugging values of   a, h and b 1   in given equation, we get

16 = 4( 3 + b 2)

first dividing both sides by 4, we get

4 = 3 + b 2

subtracting 3 from both sides, we get

4 -3 = 3 -3 + b 2

1 = b 2.