Jenna's family is going on a trip * after driving 72 miles they used 3.2 gallons of gas * after driving 72 miles, they used 3.2 gallons of gas *her family has 850 miles remaining on their road trip *the gas tank holds 15 gallons they filled the gas tank at the start of the road trip. they plan to only stop to fill up when their gas tank nears empty. there are plenty along the route. how many additional stops for gas will they need to make to get to their destination? explain your answer using numbers words and/or pictures

2

Step-by-step explanation:

Given Data:

total distance= 850 miles

gas tank holds gas= 15 gallons

mileage = 72/3.2 miles/gallon

if

72 miles uses= 3.2 gallon

then

850 miles uses= x gallons

by cross-multiplication we get

72x=3.2(850)

x=37.778

i.e. 850 miles will use 37.7778 gallon of gas

Asgas tank holds 15 gallons

number of times gas tank is used up= 37.3/15

                                                            = 2.518

rounding off

number of times gas tank is used up=3

As they filled the gas tank at the start of the road trip, hence 3-1=2

ADDITIONAL STOPS FOR GAS WILL THEY NEED TO MAKE TO GET TO THEIR DESTINATION =2 !

c: y > - 1/6x + 1

step-by-step explanation:

dashed line - meaning this < or > also not equal

solid line - meaning this < or > also equal

your answer is c because y > means up & it's shaded up, but y < means down

hope this ! : )

answer:   35 % is the probability of a late departure or an early arrival.

step-by-step explanation:

let l represents the late departure and e represents the early departure.

then, according to the question,

p(l) = 12 %,   p(e) = 27 % and = 4 %

and, we have to find out,

but, we know that,

which is the required equation that will use to find the probability of a late departure or an early departure.

therefore,   the probability of a late departure or an early arrival =   35 %