Write the equation of a line that is perpendicular to the given line and that passes through the given point. y=2/3x+9 m (–6, 5)

Write the equation of a line that is perpendicular to the given line and that passes through the given point. y=2/3x+9 m (–6, 5)

y = -3/2x - 4

y = mx + c

*m = gradien

•>looking for gradients

y=2/3x+9

m1 = 2/3

m2 = -3/2

•>line equation (-6,5)

y - y1 = m(x - x1)

y - 5 = -3/2(x - (-6))

y - 5 = -3/2(x + 6)

y - 5 = -3/2 - 9

y = -3/2x - 9 + 5

y = -3/2x - 4

answer rather than having to add and subtract the measurements of the semi-circle, notice that the semicircle to the left of ad is actually identical in area to the blank semicircle-shaped space to the left of bc. so if we transferred the red semicircle into the blank space, we would end up with a square of side length 24 cm. the area of a square is s^2 = 24^2 = 676 cm^2.

u also answered this so i think u would know but i am here to

put in or use mine