Can 2.5, the square root of 18 and 5 form a right triangle?

Step-by-step explanation:

if 2.5, sqrt(18), and 5 make up the sides of a right triangle, then they must satisfy A^2+B^2=C^2, where C is the longer side (hypotenuse).

In this case, 5 is the greater of the 3, so let's see if it satisfies our equation:

2.5^2+sqrt(18)^2=5^2

-> 6.25+18 = 24.25 =/= 25

-> Therefore the answer is a resounding no.

c. y = 1/4 x + 5

step-by-step explanation:

first, put the equation of the line on the graph into slope-intercept form

(y = mx + b):   y = -4x + 8

second, a perpendicular line has to have "an opposite/reciprocal slope" to the original slope. so, find the "m" value in your original equation (it's -4, right? )

original slope: m = -4   perpendicular slope: change the sign to its opposite and find the reciprocal ("flip" the number)

new slope is now positive (b/c the original slope was negative 4), and it's 1/4 (not the original slope of 4 or 4/1)

just keep asking questions until you have a better understanding.

step-by-step explanation: