What are the roots of x in -10x2 + 12x − 9 = 0?

Step-by-step explanation:

Use the Quadratic formula:

You can identify that, in this case:

Now you need to substitute these values into the formula:

Remember that:

Therefore,rewriting and simplifying, you get:

Then, you get the following roots:

x = 3[2 + i√-6]/10 or x = 3[2 - i√-6]/10

Step-by-step explanation:

Formula

Solution of a quadratic equation ax² + bx + c = 0

x = [-b ± √(b² - 4ac)]/2a

To find the solution

It is given that,

-10x² + 12x - 9 = 0

here a = -10, b = 12 and c = -9

x = [-b ± √(b² - 4ac)]/2a

  = [-12 ± √(12² - 4* -10 * -9)]/2 * -10

 = [-12 ± √(144 - 360)]/-20

 =[12 ± √-216]/20

 = [12 ± i6√-6]/20

 =  [6 ± i3√-6]/10

 = 3[2 ± i√-6]/10

x = 3[2 + i√-6]/10 or x = 3[2 - i√-6]/10

y=mx+b

step-by-step explanation:

m slope, b y-intercept

answer: i literally just answered this question but they want me to do it again

step-by-step explanation: