Rectangle a has a length of 2x + 6 and a width of 3x. rectangle b has a length of x + 2 and an area of 12 square units greater than rectangle a's area. what is a simplified expression for the width of rectangle b? x + 2 x + 1 6x + 6 6(x + 2)(x + 1)

So the final answer would be width is 6x + 6

Step-by-step explanation: The formula for Area is Length x width.

So A = (2x + 6)(3x) and the result is: 6x^2 + 18x

Now, let y be the width of rectangle B.

(x+2) (y) = 6x^2 + 18x + 12

(x+2) y = 6(x+1)(x+2)

y = 6(x+1)

answer: 75°

step-by-step explanation:

∠esk is the supplement of ∠edk, so is 100°. ∠esd = 1/2·arc ed, so is 25°.

since ∠esk = ∠esd + ∠dsk

you have 100° = 25° + ∠dsk . .

fill in known values 75° = ∠dsk . . . . .

subtract 25°

step-by-step explanation: