Big ed’s car dealership is running a special on 2008 trucks. big ed offers financing at a rate of 6.71% on a loan with a term of 36 months, but he requires the customer to make a down payment of 15% of the cost of the vehicle. you are interested in a car crusher truck that costs $25,230. not including the down payment, how much will you pay over the lifetime of the loan? a. $27,924.84 c. $23,735.88 b. $25,789.32 d. $21,445.50 select the best answer from the choices provided a b c d

C

Step-by-step explanation:

25,230 x .15= 3,784.50

25,230- 3,784.50= 21,535

21,535/36= 598.20833

598.20833 x 1.0671= 638.348109

638.348109 x 36= 22,980.5319

Letter C $23,735.84.The result varies a few dollars, because during the solution an adjustment was made to the decimals.

Step-by-step explanation:

1. Define the price of the vehicle you are going to buy with the dealer or seller

Principal: $25230

Rate= 6.71%

N= 36 months

Down payment=15% of the cost of the vehicle= (25230*0.15)=$3784.50

25230-3784.50=21445.5

2. Apply the amortization formula to determine the monthly payments. With this taxation, you will determine the payments applied to the principal and the copper of interest.

A=P*(r(1+r)^{n})/((1+r)^{n}-1).

A= amortization or monthly payments.

P=Principal

R=interest rate

N= the total number of months

a.Calculate the monthly interest rate. The annual interest rate is 6.71% percent. Divide it by 12 to get the monthly interest rate. The monthly interest rate is 0.5592 percent (6.71/12 = 0.5592)  

A=21445.5*(0,005592 (1+0,005592)^{{36}})/(1+0,005592)^{{36}}-1.

A=21445.5*(0,00683/0,2223)

A=21445.5*0,03072=658.90

Total of the payment= 658.90*36=23720.40

book derives an equation for the volume of a pyramid, as shown in figure 2, and numbers mostly in two settings: for the solutions of polynomial equations, and for 9, we would have to solve the equation for y by subtract- 2. the point (1,. 2) is the center of the circle whose equation is x2 y2. 2x. 4y p.w.c. davies.

step-by-step explanation:

part a

answer: a reasonable domain is where n is a real number. so n can be between 0 and 10. both endpoints are included.

work shown:

n is the number of days after the experiment starts. the smallest n can be is n = 0 which means that 0 days have gone by, and we're at the start. to find out how large n should be, then replace f(n) with 16.13 and solve for n. use logarithms to isolate the exponent.

f(n) = 12*(1.03)^n

16.13 = 12*(1.03)^n

16.13/12 = (1.03)^n

1.34416666666667 = (1.03)^n

(1.03)^n = 1.34416666666667

log[ (1.03)^n ] = log[ 1.34416666666667 ]

n*log[ 1.03 ] = log[ 1.34416666666667 ]

n = log[ 1.34416666666667 ]/log[ 1.03 ]

n = 10.0062999823929

this rounds to n = 10 which is fairly close but not 100% perfect. so this is the largest n can be.

note: if you plug n = 10 into f(n), you'll get roughly 16.127 which rounds to 16.13 (this comes up again in part c)

=====================================

part b

answer: the y intercept is 12. it represents the starting height of the plant in cm.

work shown:

plug n = 0 into the f(n) function. simplify

f(n) = 12*(1.03)^n

f(0) = 12*(1.03)^0

f(0) = 12*(1)

f(0) = 12

on day n = 0, aka the starting point, the height f(n) is 12 cm

=====================================

part c

answer: the average rate of change is approximately 0.43061036458991 (round however you need to). this represents the average growth rate from day n = 3 to day n = 10. so the plant grew roughly 0.43 cm per day during this timespan, assuming you round to 2 decimal places.

work shown:

compute f(3)

f(n) = 12*(1.03)^n

f(3) = 12*(1.03)^3

f(3) = 13.112724 < we'll use this later

compute f(10)

f(n) = 12*(1.03)^n

f(10) = 12*(1.03)^10

f(10) = 16.1269965521294 < we'll use this later

now use the formula below with a = 3 and b = 10

aroc = average rate of change

aroc = [ f(b) - f(a) ]/[ b - a ]

aroc = [ f(10) - f(3) ]/[ 10 - 3 ]

aroc = (16.1269965521294 - 13.112724)/(10 - 3)

aroc = 3.0142725521294/7

aroc = 0.43061036458991

round this however you need to

note: the plant grew approximately 3.01 cm over 7 days, so roughly 0.43 cm per day is the average growth rate (if you were to round to 2 decimal places).