What is the length of segment tr?

units

8 units

Step-by-step explanation:

Using the perpendicular bisector theorem, if we know that TQ is 8 units, then RT must be 8 units as well.

8

Step-by-step explanation:

Step 1: Find the length of segment TS (I will call this as y)

Method: Pythagoras

10² = y² + 8²

 = 100-64 = y²

y = square root of 36

y = 6

Step 2: Use the method of Pythagoras to find RT = (x)

10² = x² + 6²

x² = 100 - 36

x = 64 square root

x = 8

45

step-by-step explanation:

x = ±sqrt(10)

step-by-step explanation:

5 - 2x² = -15

subtract 5 from each side

5-5 - 2x² = -15-5

-2x^2   = -20

divide by -2 on each side

-2x^2   /-2= -20/-2

x^2 =10

take the square root on each side

sqrt(x^2 )=±sqrt(10)

x = ±sqrt(10)

check:

5 - 2x² = -15

+sqrt(10)

5 - 2(sqrt(10))² = -15

5 -2(10) = -15

5 -20 = -15

-15 = -15

-sqrt(10)

5 - 2(-sqrt(10))² = -15

5 -2(10) = -15

5 -20 = -15

-15 = -15