Agroup of 10 students participate in chess club, karate club, or neither. let event a = the student is in karate club. let event b = the student is in chess club.

one of these students is randomly selected. what is p(a/b)?

option A

2/4 = 0.5

Step-by-step explanation:

Given in the questions that,

number of student in chess club = 4

P(B) = 4/10

number of student in karate club = 6

P(A) = 6/10

number of students who are both in chess and karate club = 2

P(A∩B) = 2/10

total number of students 10

Formula to use

answer: 25 is the correct answer

step-by-step explanation: