An experiment consists of randomly selecting a marble from a bag, keeping it, and then selecting another marble. the bag contains 4 blue marbles, 3 green marbles, 7 red marbles, and 1 yellow marble. what is the probability of selecting a red marble and then a blue marble? question 3 options: 20% 13.33% 10% 16.66%

13.33%

Step-by-step explanation:

First we need to find the total number of marbles

4 blue marbles+ 3 green marbles+ 7 red marbles+ 1 yellow marble= 15

The probability of a red marble = number of red marbles over the total marbles

P(red) = red/total = 7/15

We keep the marble.  There are now 6 red marbles

4 blue marbles+ 3 green marbles+ 6 red marbles+ 1 yellow marble= 14

We have 14 marbles in the bag

The probability of a blue marble = number of blue marbles over the total marbles

P(blue) = blue/total = 4/14 = 2/7

Then we multiply the probabilities together

P(red,blue0 = 7/15 * 2/7 = 2/15 =.13333333 = 13.33%

unless if u could do my questions, if not i wouldn't want to

shift 4 units up, and 1 unit left.

it will translate f(x) = 3^x to g(x) = 3^(x+1) + 4