Me out !
a spinner has 10 equally sized sections, 6 of which are gray and 4 of which are blue. the spinner is spun twice. what is the probability that the first spin lands on blue and the second spin lands on gray? write your answer as a fraction in simplest form.

6/25

Step-by-step explanation:

To solve this we first need to know the probability for landing on a gray section and the probability of landing on a blue section:

Probability of gray - 6/10 or 3/5

Probability of blue - 4/10 or 2/5

Now that we know this, the question asked us to find the probability we will spin blue and than gray. We know that these events are independent of each other meaning that one outcome will not affect the probability of another outcome. Therefore in order to find the probability of blue then gray we can just multiply the probability of landing on gray (3/5) by the probability of landing on blue (2/5).

3/5 x 2/5 = 6/25

I hope this helps!

-The Business Man

(0,-3) see attached graph

step-by-step explanation:

a. to solve the system, graph the two equations.

x = y+3 becomes y=x-3 has m=1/1 and b=-3. start at (0,-3) on the y-axis and plot a point. then move up 1 unit and 1 unit to the right. plot a point and connect.

y=-4x+3 has m =-4/1 and b=-3. start at (0,-3) on the y-axis and plot a point. then move down four units and to the right 1 unit. plot a point and connect.

the solution is the point (x,y) where the two lines intersect. by the graph below it is (0,-3).

b. to solve by substitution, substitute y = -4x-3 into x= y+3

x= (-4x-3) +3

x=-4x

5x=0

x=0

now substitute x = 0 back in to find y.

y= -4(0)-3

y=0-3

y=-3

solution is (0,-3)

c. use elimination by adding the equations together.

x-y=3

4x+y=-3

5x=0

x=0

then substitute into one equation to find y.

y=-4(0)-3

y=-3