Which is equivalent to (9y2-4x)(9y2+4x) , and what type of special product is it?

81y^4 - 16x^2, difference of squares.

Step-by-step explanation:

So we need to expand the following product:

(9y2-4x)(9y2+4x) = 9y2*9y2 + 4x*9y2 - 4x*9y2 -4x*4x = 81y^4 - 16x^2

And this type of product is the difference of squares.

Step-by-step explanation:

The given expression is ( 9y² - 4x) (9y² + 4x)

We will simplify the given expression

(9y² - 4x) (9y² + 4x) = 9y² (9y² + 4x) - 4x (9y² + 4x)  [Distributive property]

= 81y⁴ + 36xy² - 36xy² - 16x²

= (81y⁴ - 16x²)

This simplified form is the difference of squares of terms (9y²) and (4x)

n

step-by-step explanation: