Awall with an area of (3x2 + 4x + 1) square units has a rectangular window that has a width of (x + 2) units and a length of (x + 1) units. the wall also has a built-in shelving unit that occupies an area of (x2 + 5x + 6) square units of wall space. if the wall is to be covered with wallpaper, how much wallpaper will be required?

the total available area = (3x^2 + 4x + 1) - (2x^2 + 8x + 8) = x^2 - 4x - 7

Step-by-step explanation:

The question seems to ask available area and not how much wallpaper is required. Let's calculate the area of the rectangular window. Area of a rectangle = Length * Breath Area = (x + 2) * (x + 1) = x^2 + 3x + 2 The wall also has a built- in shelving unit that occupies an area of (x^2 + 5x + 6). So total area occupied by the rectangular wall and shelf is (x^2 + 3x + 2) + (x^2 + 5x + 6) = 2x^2 + 8x + 8. If the wall is to be covered with wallpaper

Sorry for the wait

sum= when you add is how much the whole amount is

distance= when you use angles and it means how far it goes

step-by-step explanation:

i think that you should ask google for the answer to that problem because if we don't know it google does