In the system shown below, what are the coordinates of the solution that lies in quadrant iv?

write your answer in the form (a, b) without using spaces

The coordinates of the solution that lies in quadrant IV are (2, -5)

Step-by-step explanation:

We have 2 equations, the first of an ellipse and the second of a circumference.

To solve the system solve the second equation for x and then substitute in the first equation

So Substituting in the first equation we have

Now we must factor the quadratic expression.

We look for two numbers that multiply as a result -5 and add them as result 4.

These numbers are -1 and 5.

Then the factors are

Therefore the system solutions are:

;

In the 4th quadrant the values of x are positive and the values of y are negative.

So we take the negative value of y and substitute it into the system equation to find x

, and

In the 4th quadrant the values of x are positive

So we take the positive value of x

the coordinates of the solution that lies in quadrant IV are (2, -5)

according to the triangle sum theorem, all the angles in a triangle must add up to 180 degrees. if we know one angle is already 90, we do 180-90=90. the other 2 angles must add up to 90, exactly.

step-by-step explanation:

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